EXERCISE 6.2 sum no.4 (class 10th )
EXERCISE 6.2 SUM 4. In a figure, DE∥AC and DF∥ AE, prove that BE/FE=BE/EC. Solution:- Given:- DE∥AC and DF∥ AE To Prove :- BE/FE=BE/EC Proof:- In △ABC DE∥AC Because ( if a line is drawn parallel to one side of triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio .) BE/EC=BD/DA .......(1) and, In △AEB DF∥ AE Because ( if a line is drawn parallel to one side of triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio .) BF/FE= BD/DA ......(2) From (1) and (2) BE/FE=BE/EC Hence proved